5v^2+3v-2=0

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Solution for 5v^2+3v-2=0 equation: 



5v^2+3v-2=0

a = 5; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·5·(-2)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$


$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-7}{2*5}=\frac{-10}{10}
=-1
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+7}{2*5}=\frac{4}{10}
=2/5
$

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